Finding Subarrays with Given Sum | Left and Right Indexes | Programming | Leetcode Java Problem смотреть онлайн

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In this video, we will explore a Java solution to a common problem. Given an unsorted array A of size N that contains only positive integers, we need to find a continuous sub-array that adds up to a given number S. Additionally, we are required to return the left and right indexes (1-based indexing) of that subarray. If there are multiple subarrays with the same sum, we will return the indexes of the subarray that appears first when moving from left to right.

Let's look at a couple of examples to understand the problem better:

Example 1:
Input: N = 5, S = 12, A[] = {1,2,3,7,5}
Output: 2 4
Explanation: The sum of elements from the 2nd position to the 4th position is 12.

Example 2:
Input: N = 10, S = 15, A[] = {1,2,3,4,5,6,7,8,9,10}
Output: 1 5
Explanation: The sum of elements from the 1st position to the 5th position is 15.

To solve this problem, we will implement the function subarraySum(), which takes the array 'arr', the size 'N', and the target sum 'S' as input parameters. The function will return an ArrayList containing the starting and ending positions of the first occurring subarray with the sum equal to S. The indexes in the array will be according to 1-based indexing. If no such subarray is found, the function will return an ArrayList containing only one element, which is -1.

Stay tuned for the step-by-step solution to this problem. We will discuss the approach, explain the code implementation in Java, and analyze the time and space complexity of the solution.

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Keywords: Java tutorial, subarray, given sum, left and right indexes, programming problem, unsorted array, positive integers, continuous subarray, target sum, multiple subarrays, 1-based indexing, efficient approach, step-by-step implementation, time complexity, space complexity, programming tutorials

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