Unix & Linux: Skip the first 6 lines/rows in a text file with awk (4 Solutions!!)

Unix & Linux: Skip the first 6 lines/rows in a text file with awk


The Question: How can I skip the first 6 lines/rows in a text file (input.txt) and process
the rest with awk? The format of my awk script (program.awk) is:
BEGIN {
}

{
process here
}

END {

}
My text file is like this:
0
3
5
0.1 4.3
2.0 1.5
1.5 3.0
0.3 3.3
1.5 2.1
.
.
.
I want to process the file starting from:
0.3 3.3
1.5 2.1
.
.
.

Solutions: Please watch the whole video to see all solutions, in order of how many people found them helpful

== This solution helped 37 people ==
Try:
awk 'FNR ＞ 6 { #process here }' file

== This solution helped 75 people ==
Use either of the two patterns:
NR＞6 { this_code_is_active }
or this:
NR＜=6 { next }
{ this_code_is_active }
Use FNR instead of NR if you have many files as arguments to awk and want to
skip 6 lines in every file.

== This solution helped 5 people ==
You may also skip an arbitrary number of lines at the beginning or the end of
the file using head or tail programs.
For your concrete question,
tail input.txt -n+7 | program.awk
will do, provided your program.awk file is executable. Otherwise, you may use
tail input.txt -n+7 | awk -f program.awk
This way, you will spare a comparison for each line and you don't need to
change the logic of your AWK code.
tail will start streaming text starting at the seventh line, skipping the six
first lines.
This will not be a huge deal in performance, especially if text process is
simple thanks to caching. However, for long files and repeated use in cloud
environment may save some cost.

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